How to pass "name" from void arg
Posted: Mon Jan 25, 2021 8:46 am
How can i get "name" in callback function?
https://github.com/espressif/esp-idf/bl ... ple_main.c
Code: Select all
esp_timer_handle_t oneshot_timer;
static void oneshot_timer_callback(void* arg)
{
//printf("%s\n",(char*)arg ); NEED NAME FROM ARG ----- .name = "one-shot-name"
int64_t time_since_boot = esp_timer_get_time();
ESP_LOGI(TAG_TIMER, "One-shot timer called, time since boot: %lld us", time_since_boot);
ESP_ERROR_CHECK(esp_timer_delete(oneshot_timer));
}
void myfunc.... {
const esp_timer_create_args_t oneshot_timer_args = {
.callback = &oneshot_timer_callback,
.arg = (void*) oneshot_timer,
.name = "one-shot-name"
};
ESP_ERROR_CHECK(esp_timer_create(&oneshot_timer_args, &oneshot_timer));
ESP_ERROR_CHECK(esp_timer_start_once(oneshot_timer, 5000000));
ESP_LOGI(TAG_TIMER, "Started timers, time since boot: %lld us", esp_timer_get_time());
}